This month’s Train challenges you to swap two variables’ values with out utilizing a 3rd variable. It’s an answer broadly out there on the Web, however your job is to determine the method with out wanting elsewhere.
I confess that I noticed this answer months in the past and marveled at it. However I forgot the specifics. Slightly than look it up once more, I got down to devise it by myself, utilizing solely my imprecise reminiscence of the mathematical operations used on the 2 variables to swap values. Listed below are the three statements I take advantage of:
b = b + a;
a = b - a;
b = b - a;
Sure, it took me some time to hone this end result, which works for each signed and unsigned values. Determine 1 helps illustrate how the operation works.
Successfully, variable b
turns into what would in any other case be swapping variable c
. First it holds the sum of a
and b
: b = b + a
When unique a
is subtracted, what’s left over is b
, which is assigned to a
: a = b - a
Lastly, the brand new worth of a
(unique b
) is subtracted from new b
, which yields the unique worth of a
, assigned to b
: b = b - a
It took my mind a couple of minutes to just accept this answer. I even tried to condense it to solely two statements, however both I’m not that good or such an answer isn’t attainable. Regardless, right here is the complete answer:
2023_06-Train.c
#embody <stdio.h> int essential() { int a,b; printf("Enter worth A: "); scanf("%d",&a); printf("Enter worth B: "); scanf("%d",&b); printf("Earlier than: A=%d, B=%dn",a,b); b = b + a; a = b - a; b = b - a; printf("After: A=%d, B=%dn",a,b); return(0); }
After scripting this code, I checked the interwebs to see what I discovered earlier, the inspiration for this Train. Yep, I obtained it proper. I hope you probably did as properly.