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Binary Tree Most Path Sum Program in Go (Golang)


A  binary tree is given. The target is to search out the utmost Path Sum in that binary tree.  A path in a binary tree is a sequence of nodes which might be related to one another. Every node solely seems as soon as within the Most Path Sum

Instance 1

Output: 16
Most Sum Path is: 4->2->1->3->6

Instance 2

Output: 14
Most Sum Path is: 5->3->6

The concept is to trace beneath 4  values at each node

  • b = root.Val + leftSubTreeMaxSum
  • c  = root.Val + rightSubTreeMaxSum
  • d =  root.Val + leftSubTreeMaxSum+  rightSubTreeMaxSum

Then

  • Max sum at a given node is given max of (a,b,c,d)
  • The return worth within the recursive name can be a max of (a,b,c).  Why? It’s because solely the trail of a or b or c represents a path that may be taken into consideration on the guardian node. d can’t be taken into consideration as a result of it turns into an invalid path. To know this with an instance think about the binary tree in instance two above. Path 5->3->6 can’t embody guardian node -5 in its path as a result of it turns into an invalid path.

Under is this system for a similar

bundle foremost

import (
	"fmt"
	"math"
)

kind TreeNode struct {
	Val   int
	Left  *TreeNode
	Proper *TreeNode
}

func maxPathSum(root *TreeNode) int {
	res := math.MinInt64

	maxPathSumUtil(root, &res)
	return res
}

func maxPathSumUtil(root *TreeNode, res *int) int {
	if root == nil {
		return 0
	}

	l := maxPathSumUtil(root.Left, res)
	r := maxPathSumUtil(root.Proper, res)

	a := root.Val
	b := root.Val + l
	c := root.Val + r
	d := root.Val + l + r

	maxReturnSum := maxOfThree(a, b, c)

	maxSumPath := maxOfTwo(maxReturnSum, d)
	if maxSumPath > *res {
		*res = maxSumPath
	}

	return maxReturnSum
}

func maxOfThree(a, b, c int) int {
	if a > b && a > c {
		return a
	}

	if b > c {
		return b
	}

	return c
}

func maxOfTwo(a, b int) int {
	if a > b {
		return a
	}
	return b
}

func foremost() {
	root := &TreeNode{Val: 1}
	root.Left = &TreeNode{Val: 2}
	root.Left.Left = &TreeNode{Val: 4}
	root.Proper = &TreeNode{Val: 3}
	root.Proper.Left = &TreeNode{Val: 5}
	root.Proper.Proper = &TreeNode{Val: 6}

	output := maxPathSum(root)
	fmt.Println(output)

	root = &TreeNode{Val: -10}
	root.Left = &TreeNode{Val: 2}
	root.Left.Left = &TreeNode{Val: 4}
	root.Proper = &TreeNode{Val: 3}
	root.Proper.Left = &TreeNode{Val: 5}
	root.Proper.Proper = &TreeNode{Val: 6}
	output = maxPathSum(root)
	fmt.Println(output)

}

Output:

16
14

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Additionally, take a look at our system design tutorial sequence right here – System Design Tutorial Collection

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